Strategy puzzle
Can you bankrupt the larger army?
You are green, with 10 gold: enough for one Villager. Red has a Knight and a Spearman, and nothing you can buy beats either of them. One of the three marked hexes wins anyway. Which one?
- Red’s kingdom
- 17 hexes, with 10 gold in its capital.
- Red’s upkeep
- 24 gold a turn: 18 for the Knight and 6 for the Spearman.
- Your move
- One 10-gold Villager, bought straight onto A, B, or C.
Each hex earns 1 gold a turn. When a kingdom splits, the side with the old capital keeps the gold and any other side starts at 0. A kingdom that can’t pay its upkeep at the start of its turn loses every unit. Need a refresher?
Show the answer
The answer
A starves the Knight
Taking A cuts the Knight’s end off from the capital. That end becomes a kingdom of 6 hexes with a new capital and 0 gold. It earns 6 a turn and owes the Knight’s 18. At the start of red’s next turn, before it can move, the Knight becomes a grave.
The tempting one
B is a cut, but the Spearman can pay
B also splits red’s kingdom and strands a unit. But the Spearman’s end has 6 hexes, and a Spearman costs 6. The new kingdom pays exactly, with nothing left over, and the Spearman lives. The Knight stays on the capital’s side, where 10 hexes and 10 gold cover its 18.
The safe one
C splits nothing
C takes a hex without cutting anything off. Red earns 16 a turn instead of 17, and with 10 gold saved it still covers all 24 of its upkeep.
Count the hexes on the far side of a cut, and compare them with what the units there cost.
This position is staged on a small island in the shipped game, and every outcome is checked by its rules engine.
Find the cut in a real match
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